Джоузеф Банкс Вулкан плисе guess the value of a geometric random variable неподходящ буквално развлечение
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SOLVED:Suppose that X is a random variable with probability mass function p(x) = P(X =x) = c(0.2*), X=0, 5 . (a) (5 points) Find the value of € so that p(x) is
2. Det X be a geometric random variable with mean S. Define a new random variable Y using the following function Y-11,-31 ifXcS 2 ifX25 Where| | denote the absolute value. (a)
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If Y is a random variable with a geometric distribution E(Y) =1/p, how do you prove this? - Quora
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Solved 2. Suppose X1,..., Xn are independent and identically | Chegg.com
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SOLVED:A random variable Xhas a geometric distribution with parameter p (0 < p <1) ifand only if its probability function is given by f(x)=q-'p, x=1,2,3, where q =1-p. Find the probability generating